0.02a^2-0.08a+0.07=0

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Solution for 0.02a^2-0.08a+0.07=0 equation:



0.02a^2-0.08a+0.07=0
a = 0.02; b = -0.08; c = +0.07;
Δ = b2-4ac
Δ = -0.082-4·0.02·0.07
Δ = 0.0008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.08)-\sqrt{0.0008}}{2*0.02}=\frac{0.08-\sqrt{0.0008}}{0.04} $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.08)+\sqrt{0.0008}}{2*0.02}=\frac{0.08+\sqrt{0.0008}}{0.04} $

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